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问个AJAX的问题哈，各位帮忙，多谢！

from_zero(0,1,2...n)

(1)有个field,有个button

(2)click "Edit" button,field变成 editable input field with the previous value, button 变成 "Save" (我用返回的值 input type="text" name="my_field" value="test Ajax" 改innerHTML)

(3)改变value,再“Save”

(4)结果没有被保存，还是旧的值

Why ?

我trace 点击"Save" button后submit的值，发现新输入的“test Ajax - Modified”根本没有被catch, document.getElementById("my_field").value始终还是旧的值 - my_field 就是上面返回来的 input 的 name.

怎么解决呢？

(#4231645@0)
Last Updated: 2008-2-1
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工作学习 / 学科技术讨论 / 问个AJAX的问题哈，各位帮忙，多谢！ -from_zero(0,1,2...n); 2008-2-1 {920} (#4231645@0)
(1)有个field,有个button

(2)click "Edit" button,field变成 editable input field with the previous value, button 变成 "Save" (我用返回的值 input type="text" name="my_field" value="test Ajax" 改innerHTML)

(3)改变value,再“Save”

(4)结果没有被保存，还是旧的值

Why ?

我trace 点击"Save" button后submit的值，发现新输入的“test Ajax - Modified”根本没有被catch, document.getElementById("my_field").value始终还是旧的值 - my_field 就是上面返回来的 input 的 name.

怎么解决呢？

up一下，问题就是在 Ajax dynamically 生成的input field里,输入something 然后submit，但输入的值始终无法submit -from_zero(0,1,2...n); 2008-2-1 (#4232291@0)

Shouldn't be a problem, make sure you added the field inside the submitted form. -canadiantire(轮胎 - Do It Now); 2008-2-1 (#4232322@0)

你的Input只有name没有ID，用getElementById得不到值。 -dzhu(Daniel); 2008-2-13 (#4260285@0)

写成<input type=text id=myField name=myField value=""> -dzhu(Daniel); 2008-2-13 (#4260293@0)

@Las Vegas

问个AJAX的问题哈，各位帮忙，多谢！

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